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punxtr
zeighy wrote:
can you post the email genus sent?? maybe he has said something we had missed...


Quote:
That's fine. I don't really care about who did it. Anyways, I was just about to message you. I have something up my site. CHeck it out and try to figure it out. Yes, I already know what it is. I want to see if you can understand what it is. And yes, I did make that myself. Check back when you have figured it out.

Oh, and inform your friends about it, too. I don't have contact with them so just go ahead and share it with them. Let's just say this one's a challenge from me.

PostPosted: Tue Aug 02, 2011 12:32 pm
godder
This is all I got from Genus...
Quote:
Hello! I have something up mys site. Try and figure it out. Yes, I made it myself. And yes, I know what it is. I want to challenge you all so go and try to figure it out. Go ahead and share to your friends, too, if you want.

PostPosted: Tue Aug 02, 2011 12:32 pm
zeighy
can you post the email genus sent?? maybe he has said something we had missed...

PostPosted: Tue Aug 02, 2011 12:24 pm
godder
punxtr wrote:
I don't get this equation. It's false. Either that, or we don't understand the right-hand side correctly yet. Is it a negative sign or an A? I found nothing interesting next to the raddix point when in base 7 for 5.8013468... no repeating numbers that have any mathematical significance.


That's what I've been seeing as well. It is either a false equation or we are supposed to solve for A. Maybe the point is that the equation is incorrect? Or maybe we are just being played with.

PostPosted: Tue Aug 02, 2011 12:21 pm
punxtr
I don't get this equation. It's false. Either that, or we don't understand the right-hand side correctly yet. Is it a negative sign or an A? I found nothing interesting next to the raddix point when in base 7 for 5.8013468... no repeating numbers that have any mathematical significance.

PostPosted: Tue Aug 02, 2011 12:16 pm
Gimme20dollaz
Holy crap, they listened to me....
(I was the one who mentioned a wiki)

PostPosted: Tue Aug 02, 2011 12:09 pm
godder
Ok, back to base 7. Here is an OOG email from the PM's.

Quote:
Hello!

We've been stalking everyone through the forums and we've seen that you "might" need a wiki so we set one up. We don't really know how to use it, so we'll assume you already do. Don't worry, we're learning as well. We think keeping the wiki fully open to the public (yes, like completely open to anyone) will allow anyone who had a part in this ARG to have their own share. After all, an ARG is a community game and there's no better way to see the ARG then from the eyes of the community.

We do hope you do build up this wiki, and tailor it on how you see fit. Don't worry, if you don't use it, it's perfectly fine for us. We're here to provide you with what you need as we see fit. Yes, we know we should have set this up long ago, but we don't really know how to use it. Good luck!

LINK: http://argwiki.failtechnologies.com

FAILTECH ARG Team


EDIT: Check out the logo in the top left of the wiki page. A planet with 3 moons. Cool.

PostPosted: Tue Aug 02, 2011 11:47 am
godder
zeighy wrote:
I got A=5.80135 if I calculated this in base 10 all the way... I suppose that would still be the answer if I calculated it in base 7... however, what bothers me is the decimal... how do you convert a decimal into base 7 "decimal"


Technically it would be such a small number it would almost be the exact same any way. It wouldn't matter too much, especially considering significant digits. Work beckons. Be back momentarily.

PostPosted: Tue Aug 02, 2011 11:15 am
punxtr
zeighy wrote:
I got A=5.80135 if I calculated this in base 10 all the way... I suppose that would still be the answer if I calculated it in base 7... however, what bothers me is the decimal... how do you convert a decimal into base 7 "decimal"


Simple, multiply the decimal portion by 7, writing down and removing the integer part each time, and repeating this until you have an absolute true error less than whatever you specify.

PostPosted: Tue Aug 02, 2011 11:01 am
zeighy
I got A=5.80135 if I calculated this in base 10 all the way... I suppose that would still be the answer if I calculated it in base 7... however, what bothers me is the decimal... how do you convert a decimal into base 7 "decimal"

PostPosted: Tue Aug 02, 2011 10:34 am
godder
zeighy wrote:
godder wrote:
This is the equation as I see it.

(545/1405)+((13-506)/(132/3))=(-24/3)

That's in base 7. Does that look right to you Zeighy? The answer is 6, but I'm having a hard time getting the left side to agree. It's been a long time since I messed with other base systems.


I think while the numbers are arranged in reverse, the operation still goes from left to right, just like the example he gave on basics... 222-1=221

so instead of 13-505 it was 505-13

this is what I got:

((5401+1405) / (45/3)) + ((505-13) / (132/3) = 24A / 3

I think the - was actually A since that's the letter rather a negative sign... just a thought...

so

(10106/201)+(462/33) = 24A/3 <<< base 7

24.8080 + 10 = 18A/3 <<< base 10, I don't know how to convert the decimal to base decimal... Neutral can we actually compute with decimals? I'm stuck here

Ok, still fixing my mistakes. I'll see if I can make something work. Lets see what I can come up with.

PostPosted: Tue Aug 02, 2011 10:29 am
zeighy
godder wrote:
This is the equation as I see it.

(545/1405)+((13-506)/(132/3))=(-24/3)

That's in base 7. Does that look right to you Zeighy? The answer is 6, but I'm having a hard time getting the left side to agree. It's been a long time since I messed with other base systems.


I think while the numbers are arranged in reverse, the operation still goes from left to right, just like the example he gave on basics... 222-1=221

so instead of 13-505 it was 505-13

this is what I got:

((5401+1405) / (45*3)) + ((505-13) / (132/3) = 24A / 3

I think the - was actually A since that's the letter rather a negative sign... just a thought...

so

(10106/201)+(462/33) = 24A/3 <<< base 7

24.8080 + 10 = 18A/3 <<< base 10, I don't know how to convert the decimal to base decimal... Neutral can we actually compute with decimals? I'm stuck here


scratch that, let me redo this

PostPosted: Tue Aug 02, 2011 10:21 am
godder
This is the equation as I see it.

(545/1405)+((13-506)/(132/3))=(-24/3)

That's in base 7. Does that look right to you Zeighy? The answer is 6, but I'm having a hard time getting the left side to agree. It's been a long time since I messed with other base systems.

Edit: Oops, I already see where I messed up. Try this...

((545+1405)/(45*3))+((13-50 6 5)/(132/3))=(-24/3)

See if that looks right now.

PostPosted: Tue Aug 02, 2011 9:56 am
zeighy
godder wrote:

Here is the basics image run down. It is a base 7 system. And they have their numbers in reverse order from ours.

1+1=2 .......... 146+134=313
1-1=0 .......... 146+1=150
1*1=1 .......... 111+1=112
2/2=1 .......... 222-1=221
1+1=2 .......... 6/3=2

I'm working on the other one now


pssssh, so that's why I didn't get it... Neutral the numbers were written in reverse.... Neutral

PostPosted: Tue Aug 02, 2011 9:22 am
godder
zeighy wrote:
godder, can you post what you got from the image named "basic" first? I can't get it... Neutral it doesn't make sense to me... I know I got some of them, like the addition and subtraction part... pretty much it... Neutral


Here is the basics image run down. It is a base 7 system. And they have their numbers in reverse order from ours.

1+1=2 .......... 146+134=313
1-1=0 .......... 146+1=150
1*1=1 .......... 111+1=112
2/2=1 .......... 222-1=221
1+1=2 .......... 6/3=2

I'm working on the other one now

PostPosted: Tue Aug 02, 2011 9:15 am
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