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 Forum index » Diversions » Perplex City Puzzle Cards » PXC: Blue Puzzle Cards
[Puzzle] Blue #139 This Sentence Is False
Moderators: AnthraX101, bagsbee, BrianEnigma, cassandra, Giskard, lhall, Mikeyj, myf, poozle, RobMagus, xnbomb
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lauriek
Boot

Joined: 23 Aug 2005
Posts: 68
Location: Kent, UK

 		I don't think a blue card is going to be that easy, the others I have certainly don't seem to be!

Spoiler (Rollover to View):

I wrote these two scripts which come up with the same answers as helper...

basic stepper script
randomized stepper

Both pages use some pretty simple javascript to do the stepping...

(note its NOT the randomizer button on the second script which makes it find the second answer, its a random element in the 'update number when its wrong' routine which only updates the number 50% of the time it's wrong)


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PostPosted: Fri Aug 26, 2005 5:52 pm
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lauriek
Boot

Joined: 23 Aug 2005
Posts: 68
Location: Kent, UK

 		Oh and another /possible/ answer

Spoiler (Rollover to View):

the number of times the digit 0 appears on this puzzle is ONE
the number of times the digit 1 appears on this puzzle is ONE
the number of times the digit 2 appears on this puzzle is ONE
the number of times the digit 3 appears on this puzzle is ONE
the number of times the digit 4 appears on this puzzle is ONE
the number of times the digit 5 appears on this puzzle is ONE
the number of times the digit 6 appears on this puzzle is ONE
the number of times the digit 7 appears on this puzzle is ONE
the number of times the digit 8 appears on this puzzle is ONE
the number of times the digit 9 appears on this puzzle is ONE

But I think this is excluded by the use of the word DIGIT in the question..

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PostPosted: Sat Aug 27, 2005 9:58 am
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RobDixon
Boot


Joined: 23 Nov 2004
Posts: 41
Location: San Rafael, California

 		lauriek,

Thanks for posting the solver programs!

I really like the ONE answer, but you're right, I think it won't count since the rules say to add digits.

Here's another variation that only involves digits. It seems to fit the rules, though it's not quite as simple as the first two solutions:

Spoiler (Rollover to View):
THE NUMBER OF TIMES THE DIGIT 0 APPEARS IN THIS PUZZLE IS 10
THE NUMBER OF TIMES THE DIGIT 1 APPEARS IN THIS PUZZLE IS 11
THE NUMBER OF TIMES THE DIGIT 2 APPEARS IN THIS PUZZLE IS 02
THE NUMBER OF TIMES THE DIGIT 3 APPEARS IN THIS PUZZLE IS 01
THE NUMBER OF TIMES THE DIGIT 4 APPEARS IN THIS PUZZLE IS 01
THE NUMBER OF TIMES THE DIGIT 5 APPEARS IN THIS PUZZLE IS 01
THE NUMBER OF TIMES THE DIGIT 6 APPEARS IN THIS PUZZLE IS 01
THE NUMBER OF TIMES THE DIGIT 7 APPEARS IN THIS PUZZLE IS 01
THE NUMBER OF TIMES THE DIGIT 8 APPEARS IN THIS PUZZLE IS 01
THE NUMBER OF TIMES THE DIGIT 9 APPEARS IN THIS PUZZLE IS 01


Just doing my bit to help sow the seeds of confusion. Wink

PostPosted: Tue Aug 30, 2005 7:22 pm
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JebJoya
Unfettered


Joined: 13 Apr 2005
Posts: 679
Location: UK

 		interestingly, the site only asks for one solution to give you the points, even though the card clearly asks for both... hey ho...

Jeb
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PostPosted: Thu Oct 20, 2005 11:07 pm
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ReeKorl
Guest


 		Not sure how relevant this is:

Spoiler (Rollover to View):
but has anyone else noticed the single digit answer (1732111211) is the same as the first ten digits of the square root of three?


PostPosted: Mon Nov 07, 2005 10:38 am
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looosy
Boot

Joined: 04 Aug 2005
Posts: 48
Location: Kent, England
Quote:
has anyone else noticed the single digit answer (1732111211) is the same as the first ten digits of the square root of three?


Interesting! so many things keep pointing back to 3 and cubed....

Very clever Wink
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PostPosted: Mon Nov 07, 2005 11:55 am
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Schmooze
Kilroy

Joined: 27 Nov 2005
Posts: 1
Location: Somerset, UK

 		Third Solution
removed coz I should have looked before I lept lol

PostPosted: Sun Nov 27, 2005 2:12 pm
Last edited by Schmooze on Mon Nov 28, 2005 6:42 pm; edited 1 time in total
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Hunting4Treasure
Unfettered


Joined: 06 Aug 2005
Posts: 385
Location: Tampa Bay Area, FL USA
ReeKorl wrote:
Not sure how relevant this is:

Spoiler (Rollover to View):
but has anyone else noticed the single digit answer (1732111211) is the same as the first ten digits of the square root of three?

I thought that was way cool, and was getting ready to try different starting points to see what I'd come up with. But, what I got for an answer is:
Spoiler (Rollover to View):
1.7320508075688772935274463415059
making the first 4 numbers the same, but then it falls apart from there.
1732111211 squared, actually turns out to be 3.000209247271886521.
Now, the first *5* numbers equal 3 (which is cool enough), but not all 10 as stated above.
Am I missing something? Or, is *that* sentence *also* false? Razz
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PostPosted: Sun Nov 27, 2005 10:55 pm
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perplextown
Kilroy

Joined: 31 Jan 2006
Posts: 1

 		NEED HELP!!!!
Hi Everyone!!

I have tried many times to solve this card but each time i enter my answers i keep getting "Incorrect"!!! or Blocked for 24hrs!!

I have tried all mentioned ideas on this thread.
Could anyone shed some light on this? or provide the solution?

Kind Regards
Perplextown

PostPosted: Tue Jan 31, 2006 2:31 pm
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sabsay
Kilroy

Joined: 07 Feb 2006
Posts: 2
Spoiler (Rollover to View):
1,7,3,2,1,1,1,2,1,1 is the correct answer


PostPosted: Wed Feb 15, 2006 8:05 pm
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kyz
Greenhorn

Joined: 10 Apr 2006
Posts: 4

 		Just in case there were more solutions, I wrote a program to exhaustively search the problem space. It checks every possibility from 1 1 1 1 1 1 1 1 1 1 to 14 14 14 14 14 14 14 14 14 14.
Code:
#include <stdio.h>

#define FOR(x) for (x = 1; x <= 14; x++)
#define ADD(x) if (x > 9) { n[x/10]++; n[x%10]++; } else { n[x]++; }

int main() {
  int c[10], n[10];

  FOR(c[9]) FOR(c[8]) FOR(c[7]) FOR(c[6]) FOR(c[5])
  FOR(c[4]) FOR(c[3]) FOR(c[2]) FOR(c[1]) FOR(c[0])
  {
    n[0] = n[1] = n[2] = n[3] = n[4] = n[5] = n[6] = n[7] = n[8] = n[9] = 1;
    ADD(c[0]); ADD(c[1]); ADD(c[2]); ADD(c[3]); ADD(c[4]);
    ADD(c[5]); ADD(c[6]); ADD(c[7]); ADD(c[8]); ADD(c[9]);

    if (c[0]==n[0] && c[1]==n[1] && c[2]==n[2] && c[3]==n[3] && c[4]==n[4] &&
        c[5]==n[5] && c[6]==n[6] && c[7]==n[7] && c[8]==n[8] && c[9]==n[9])
      printf("SOLUTION: %d %d %d %d %d %d %d %d %d %d\n",
        c[0],c[1],c[2],c[3],c[4],c[5],c[6],c[7],c[8],c[9]);
  }
  return 0;
}


Even with this search space, there are still only 2 solutions:

Spoiler (Rollover to View):
SOLUTION: 1 11 2 1 1 1 1 1 1 1
SOLUTION: 1 7 3 2 1 1 1 2 1 1


If someone wants to try a larger search space (e.g. 1 to 22), there might be something... but I doubt it.

PostPosted: Sat Apr 22, 2006 5:28 pm
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jayito
Boot


Joined: 15 Jul 2006
Posts: 26
Location: Pett, near Hastings, UK

 		I found this one really obvious and really easy, which was a shock as I normally find the cards quite hard! It's nice to know I am not completely dense!

PostPosted: Tue Jul 18, 2006 2:39 pm
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extrusion
Kilroy

Joined: 21 Jun 2006
Posts: 2

 		I just used Excel with a COUNTIF function, after sorting out the circular references stuff it complains about, the answers just appear like magic!

extrusion

PostPosted: Sat Aug 05, 2006 8:25 am
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X9Tim
Boot

Joined: 29 Sep 2006
Posts: 16

 		This card was in my first pack, and I tried to finish them all before going online.

I took it as written, i.e. "There are two possible solutions to this, what are they?"

I got one solution fairly quickly, but I was getting tired and kept making the same silly mistake.... :s

After a troubled night, I got the second answer next morning and went online to enter it. I was infuriated to find I only needed one answer! Evil or Very Mad

I think this counts as a printing error!!

--
Still I've got the points, and that's what matters! Very Happy

PostPosted: Fri Sep 29, 2006 12:58 pm
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pineapplejellynotloggedin
Guest


 		Gah!!! I solved this ages ago and have been trying at regular intervals over the past six MONTHS to a YEAR to find a second solution! I wish I'd known I didn't need it!!!

PostPosted: Sun Aug 24, 2008 10:56 pm
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