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oliverkeers13

Yes, she could. She'd realise that if Dave stayed silent, she'd have to be a different colour to Bella, the same as Charlie. She can't see anyone else, however, but after Charlie says his colour, she knows she's the other colour.

**Posted:** Thu Dec 08, 2005 1:15 pm

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BrianEnigma

**Posted:** Thu Dec 08, 2005 3:24 pm

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Scott

If you really wanted to get technical, all people could simply jar their heads fForward so their hat fFalls off. Given the picture, they don't appear to be held on very well. But i suppose that goes against the spirit of the question. And indeed, they may be bobby pinned in place. All of this assumes they didn't see the hats coming (suggesting they were blindfolded fFor the be-hatting).

**Posted:** Thu Dec 08, 2005 4:35 pm

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PuzzledPineapple · Unfettered Joined: 07 Apr 2005 Posts: 352

Generally the point of this challenge is that no one is allowed to say anything apart from the one person who chooses to guess what colour their hat is. Once that person says the right colour, they are all freed and can happily ask each other whatever question they like including, but not limited to, what colour their hat is, who the strange guy who did this to them is and what on earth anyone did to deserve it. Hence it doesn't really matter if anyone knows what colour their hat is after Charlie speaks, they're all free anyway.

The card neglects to mention whether anyone is allowed to speak other than to say the colour of their own hat, so technically, if they can actually tell who the person in front of them is (given hairstyles it shouldn't be too difficult), both Dave and Charlie could just tell Charlie and Bella respectively the colour of their hats and it would be incredibly easy. But MC rely on people like us having heard this puzzle before and remembering that there should be the extra clause about no chatting amongst themselves.

**Posted:** Fri Dec 09, 2005 12:06 pm

sabsay · Kilroy Joined: 07 Feb 2006 Posts: 2

so here goes for my first solve on this forum:

**Posted:** Tue Feb 07, 2006 6:41 am

EkoeEkoe · Greenhorn Joined: 04 Mar 2006 Posts: 3

Don't forget:

**Posted:** Mon Mar 06, 2006 4:27 pm

mcboyt · Greenhorn Joined: 26 Mar 2006 Posts: 7

**Posted:** Sun Mar 26, 2006 3:33 am

DrKra37

This is similar to a question posed by my Symbolic Logic professor the first day of class this semester. In our version there were three prisoners who could each one see the other two, and the fourth hat was simply thrown away.

**Posted:** Mon Apr 10, 2006 7:12 pm

forensick

I solved this puzzle by just figuring out that

**Posted:** Sun Apr 30, 2006 12:49 am

lonadar · Boot Joined: 30 Jan 2007 Posts: 50 Location: Indiana, USA

**Posted:** Tue Feb 20, 2007 12:35 am