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 Forum index » Diversions » Perplex City Puzzle Cards » PXC: Silver Puzzle Cards
[Puzzle] #243 Silver - Shuffled Part 2 (Read 1st Post!)
Moderators: AnthraX101, bagsbee, BrianEnigma, cassandra, Giskard, lhall, Mikeyj, myf, poozle, RobMagus, xnbomb
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DJ FreeMason
Boot

Joined: 30 Mar 2006
Posts: 66

donstobbart wrote:
He goes on to explain that he used D for a plaintext alphabet, and R for a ciphertext alphabet, which incidentally didn't work (even intrepid hero's get it wrong!!!), but by using the fact that D and R are 15 letters apart, he could take every fifteenth word of the thing that was the cipher.(It was a poem.) He got the solution from this, and went on to save the world from doom and destruction.

I have a thing about the word "should" in the clue If entropy.... and the 20 disappearing letters so I tried this theory, which of course didn't work. But, I think this might not be a bad road to wander down for a spell, to try to get the key.


Don, this concept is related to what Schneier says when he says don't use the same keyword for two messages. (A+K)-(B+K)=A-B. A professional cryptographer can deduce that if A-B=0, then the two messages have the same letter there when decoded. However, if A-B=25, then A is Z and B is A because Z is 26 and A is 1. However if A-B=-25, then vice versa. If the message is buried in the letters of the text or the words of the text, it is an interesting cipher.

PostPosted: Tue May 23, 2006 9:24 pm
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Dranioth
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Joined: 18 Apr 2006
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I warn you, Have you're trouts at the ready!

I was thinking. Is it possible that the messages are double, or possibly triple encrypted? What's i'm getting at is that They messages are first encrypted with some random cipher, Lets go with an ROT 13. Then, using those scrambled letters, they are once again encrypted with another type of cipher? Perhaps then those letters are anagrammed or something, but If that's the case, without the key wouldnt it be impossible to solve?

PostPosted: Wed May 24, 2006 1:53 am
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TekkiBreki
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Joined: 23 Apr 2006
Posts: 16
Location: Los Angeles

If the cipher is solitaire, we don't have to worry about double or triple or n-tuple encryption. I played around with Schneier's algorithm and found some stuff out. Solitaire is cyclical with period 26. If you run a plaintext through the encryption, then take the resulting ciphertext and encrypt it, you will be two steps around a circle with 26 positions, rather than two levels up or down. If you recursively encrypt 24 more times, you'll get the plaintext you started with. It's like spinning the dial on a combination lock.

Just as you can spin the dial clockwise or counterclockwise, you can run a plaintext or ciphertext through the decryption process 26 times and end up where you started.

An interesting thing I did find was at the 13th pass or 12th recursion or halfway 'round the dial or whatever you want to call it, there will be short strings of original input present in the output.

PostPosted: Wed May 24, 2006 3:36 am
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arnezami
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Joined: 14 Apr 2006
Posts: 136

Regarding double encryption. I believe it just may have been used. But not in the normal sense of the way (which TekkiBreki suggested).

Here is how they might have created the puzzle:

Lets say you have a plaintext:

Quote:
THISISTHEPLAINTEXTMESSAGE


You first add two random/meaningless pairs of 5 characters on each side:

Quote:
XXXXXXXXXXTHISISTHEPLAINTEXTMESSAGEXXXXXXXXXX


You then encrypt it (with or without using a keyphrase). For example:

Quote:
EOIJN AWQED OHEFO IHNFI OHNFO ISHNZ XOEFE XWOWD SWOEU


You then remove 10 characters on each side and encrypt the middle part again. But you do this without resetting the deck ordering (this is important). For example:

Quote:
IROQGH NDDSN CDIIRE SOPEW EFNNO


And you add the two pairs of 5 characters again:

Quote:
EOIJN AWQED IROQGH NDDSN CDIIRE SOPEW EFNNO XWOWD SWOEU


This is now the resulting cyphertext. The middle part is double encrypted.

----

To reverse the proces we would have to first decrypt this entire resulting cyphertext (with or without a keyphrase). Then remove the two pairs of 5 characters and finally decrypt the resulting text (again without resetting the deck). This should work because of the mod 26 element in the solitaire cypher.

Haven't tried it yet though. (the online version of the cypher seems to be down and i'm way too busy now in RL. maybe somebody else can) Of course the plaintext would be 108 characters long instead of 25 in the above example.

On a sidenote: the 108 (instead of 110) has been bugging me for a long time now. I can't seem to find a reasonable explanation for it Sad.

arnezami

PS. In case you were wondering the above examples are complete jibberish Wink. They are not generated by the solitaire cypher.
PPS. They could also have you a slightly different approach: first encrypt only the plaintext. Then add 10 characters on each side. And then encrypt everything again (without resetting). To decrypt: first decrypt the middle part. Then add the outer parts to that and then decrypt it all. However that would make the last 10 characters meaningless/purposeless.

PostPosted: Wed May 24, 2006 4:39 am
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arnezami
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Joined: 14 Apr 2006
Posts: 136

This is a question to those that have the card.

I was wondering how exactly the groups of 5 and the group of 3 letters are positioned.

Is it like this:

Code:
LJOTY YNGYJ BIOGI FUVMR
YKZPL LUL   FHURG IFULP


Or like this:

Code:
LJOTY YNGYJ BIOGI FUVMR
YKZPL   LUL FHURG IFULP


Or like this:

Code:
LJOTY YNGYJ BIOGI FUVMR
YKZPL  LUL  FHURG IFULP


Or more like this:

Code:
LJOTY YNGYJ BIOGI FUVMR
M YKZPL LUL FHURG IFULP


I'm asking because (depending on which one it is) it may be an indication we are "missing" two letters.

A high resolution scan of that part of the card would be great!! Cool

arnezami

PostPosted: Wed May 24, 2006 7:14 am
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poozleModerator
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Joined: 15 Aug 2005
Posts: 1090

None of the lines actually line up, it looks almost as though the second line's text is slightly larger to fit a slightly smaller ammount of text on the same line.

PostPosted: Wed May 24, 2006 8:11 am
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arnezami
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Joined: 14 Apr 2006
Posts: 136

poozle wrote:
None of the lines actually line up, it looks almost as though the second line's text is slightly larger to fit a slightly smaller ammount of text on the same line.

Ok. Thanks.

PostPosted: Wed May 24, 2006 8:24 am
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doublecross
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Joined: 25 Jul 2005
Posts: 588
Location: London, UK

Shuffled brainstorming session!

Hi all,

How about a Shuffled brainstorming session tomorrow evening on IRC (i.e. from 9 p.m. UK time on Thursday 25 May)? #syzygy channel - see Questions/Meta sticky for details.

I'm away on holiday for 8 days from Friday - no computers - so need a big fix of my addiction before I go away!
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PostPosted: Wed May 24, 2006 8:28 am
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DJ FreeMason
Boot

Joined: 30 Mar 2006
Posts: 66

9 PM UK time... That would be what 4 PM EST? How long is it going to go for, an hour, 2? If the former, I won't be able to make it, I work until about 5, if the latter, I'll be able to make the last hour.

Actually, using the idea of junk characters that arnezami suggested, that would give us a possibility of how to solve it. If the characters are junk and are all the same, we can subtract the two values using the "(A+K)-(B+K)=A-B" equation. I've been goofing around with it and it might provide an answer. Even the first disappearing 10 characters bounded on the initial 10 characters might, given the same cipher, could possibly provide an answer. That is making a huge assumption that they are the same encryption protocol.

I'll see what I can come up with. It's going to be a long day. I'm punching away at the 13th Labour duckiemonster puzzle as well as my usual cryptic crossword. I'm a puzzle fanatic.

PostPosted: Wed May 24, 2006 9:18 am
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bertyb
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Joined: 28 Nov 2005
Posts: 128
Location: London

Re: Shuffled brainstorming session!

doublecross wrote:
Hi all,

How about a Shuffled brainstorming session tomorrow evening on IRC (i.e. from 9 p.m. UK time on Thursday 25 May)? #syzygy channel - see Questions/Meta sticky for details.

I'm away on holiday for 8 days from Friday - no computers - so need a big fix of my addiction before I go away!


Like the idea, unfortunately the only night this week I could do would be tonight...after that it would be Sunday, but if it goes ahead I wish you all the best of british.

I am currently working through a couple of new ideas, should it come to anything then will post later. I am going along the lines of "re-framing the problem" at the moment and have stumbled across a couple of things that might help - but probably not.
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PostPosted: Wed May 24, 2006 10:10 am
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beglee
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Joined: 21 Oct 2005
Posts: 164

Re: Shuffled brainstorming session!

doublecross wrote:
Hi all,

How about a Shuffled brainstorming session tomorrow evening on IRC (i.e. from 9 p.m. UK time on Thursday 25 May)? #syzygy channel - see Questions/Meta sticky for details.

I'm away on holiday for 8 days from Friday - no computers - so need a big fix of my addiction before I go away!

Playing my first competitve tag rugby match of the summer 2moro at 830, so i wont be around for it either Sad
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PostPosted: Wed May 24, 2006 10:27 am
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baf
Boot

Joined: 29 Mar 2006
Posts: 46

TekkiBreki wrote:

Just as you can spin the dial clockwise or counterclockwise, you can run a plaintext or ciphertext through the decryption process 26 times and end up where you started.


Come to think of it, wouldn't this be the case for any cipher that works by adding a 26-value keystream to the plaintext? Applying the keystream means finding the sum of each plaintext value and its corresponding key value, mod 26. So applying the keystream 26 times means adding the key value 26 times, which is to say, adding the key value multiplied by 26. And for any x, (x*26) mod 26 = 0.

Quote:

An interesting thing I did find was at the 13th pass or 12th recursion or halfway 'round the dial or whatever you want to call it, there will be short strings of original input present in the output.


This makes sense too. Half of the possible key values are even, and (x*13) mod 26 = 0 when x is even. What you were seeing there is runs of even values in the keystream (B, D, F, H, etc.)

PostPosted: Wed May 24, 2006 1:58 pm
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BrianEnigmaModerator
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baf wrote:
TekkiBreki wrote:

Just as you can spin the dial clockwise or counterclockwise, you can run a plaintext or ciphertext through the decryption process 26 times and end up where you started.

Come to think of it, wouldn't this be the case for any cipher that works by adding a 26-value keystream to the plaintext?


Yep, as long as the keystream was constant and did not use any sort of feedback loops (for instance, varies based on the last 'n' values of plaintext input.) That's why they tell you not to use the same keyphrase (and deck ordering, in the case of Solitaire) for certain ciphers. If you have two or more ciphertext message, you can often work some mojo in comparing them letter-by-letter to determine the original keystream. See also: why using XOR for encryption sucks mightily.
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PostPosted: Wed May 24, 2006 2:45 pm
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justdig
Boot

Joined: 14 Aug 2005
Posts: 29

Please don't trout me for asking, but has there actually been a concerted effort at finding anagrams in the "If entropy..." message yet? I know people have mentioned it before, but has anybody spent any length of time actually trying to find anything? The name "Shuffled", combined with the apparent necessity for a key that we just don't have, combined with that apparently meaningless, oddly-worded phrase have all convinced me that an anagram is very likely.

EDIT: While I think of it, I'd also like to bring to light that the Solitaire Cipher is actually quite an assumption. As previously mentioned, the text not being in blocks of 5 is a little odd for the Solitaire, and the number of characters being exactly divisible by the number of cards in a deck would surely indicate some other playing-card related method. Also, the hint in the Sentinel about it needing to be "reframed" or something would indicate that most people are set in a view that's not correct. I know that this has also been mentioned before, but it doesn't seem to be receiving all that much consideration.

PostPosted: Wed May 24, 2006 4:11 pm
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bertyb
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Joined: 28 Nov 2005
Posts: 128
Location: London

justdig wrote:
Please don't trout me for asking, but has there actually been a concerted effort at finding anagrams in the "If entropy..." message yet? I know people have mentioned it before, but has anybody spent any length of time actually trying to find anything? The name "Shuffled", combined with the apparent necessity for a key that we just don't have, combined with that apparently meaningless, oddly-worded phrase have all convinced me that an anagram is very likely.

EDIT: While I think of it, I'd also like to bring to light that the Solitaire Cipher is actually quite an assumption. As previously mentioned, the text not being in blocks of 5 is a little odd for the Solitaire, and the number of characters being exactly divisible by the number of cards in a deck would surely indicate some other playing-card related method. Also, the hint in the Sentinel about it needing to be "reframed" or something would indicate that most people are set in a view that's not correct. I know that this has also been mentioned before, but it doesn't seem to be receiving all that much consideration.


Personally since getting this card I reckon approx 4 weeks of my life (by counting hours up) have been spent on anagramming.....perhaps I am just useless at anagrams......a high percentage of time has been spent on solitaire ciphers and there workings trying various things......approx 19 weeks......and the rest being 3 weeks looking into other areas - alternative ciphers/encryption blah blah - and still not any closer to solving the damn card.... Cursing

I am now of the opinion since the sentinel article an extra layer of encryption is on the text before solitaire can be run.....what it is I dont know.
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PostPosted: Thu May 25, 2006 9:11 am
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