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[thatslenderdude]

[Hazman]

[sweetgums]

Wait, so are we taking "ITWASHIM" as the answer? I'm still not convinced with this one, what's the point of the other non-zero numbers then?

What if this string of numbers is the key for another code like Block said?

[thatslenderdude]

That would only work if the #'s before 0 were
like this
65 54 37 90 8 87 65

[Waldorf]

[sweetgums]

[Pendet]

Okay! here's something we've been working on:

looked up on wikipedia the relative frequency of used letters in the english language, listen them from most to least common.

Match those numbers in rank to the numbers in the code, we get:


6 5 5 4 3 7 9 0 8 8 7 6 5
e t a o i n s h r d l c u

Which we took to mean "This many of these letters" resulting in this gobbeldygook:


eeeeeetttttaaaaaooooiiinnnnnnnsssssssssrrrrrrrrddddddddlllllllccccccuuuuu

With 13 zeroes (or 12 depending on where you cut off your number matching)

13 (or 12) zeroes?

[Zaria]

[FalseRoar]

So if you split it up in pairs, like the earlier codes, you end up with:
65 54 37 90 88 76 50 + 12 zeros, which could be L.

I'm not really sure how the previous codes worked, and none of these numbers appear in the previous one. I just know that if you go with the idea that each number could be two letters, (like 54 could be E or D) then you end up with an anagram that is frustratingly close to HEFAILED.

Edit: Sorry, may not have been clear. This is not it as far as I know. This answer doesn't account for 37, unless it came out to be an 'a' somehow. That's why I said close. I just don't fully understand the previous codes, assuming this one even runs the same way.

[thatslenderdude]

If this is right then who failed?
Alex?

[ledzepfilm]

^ Is this it?

[Dr.Block]

There is a difference of 1 between most of those number pairs.
6 and 5, 5 and 4, 9 and 0 (if you consider this 0 a 10), 7 and 6. Didn't we have a code before where all the number pairs followed a similar pattern? The only exceptions here would be 37, 88 and 50, where 50 might not even count...

Maybe the lower number in each pair is a letter's position in the alphabet starting from A, while the greater one is a letter's position staring from Z?

Adding each pair together you get 11 9 10 9 16 13 5. K I J I P M E.
Just throwing shit at the wall hoping something will stick.

[Bernie Buddy]

[Dr.Block]

Ok, I'm pretty sure this is the exact same kind of code that Jay was helping us solve a while back. Whatever we did to that set of numbers should work for this one.

[sweetgums]