unforum

[JTony]

Third Power and Hercules

[hexDa3m0n]

How hard would it be to rewrite RCC slightly????

[uptheblades]

omicron sigma wrote:- ..
A string of five cows (or perhaps five cow skulls) appears on the surface of an Advanced Micro Devices (AMD) 80486DX4 microprocessor. An anonymous engineer has informed us that the heads represent the internal codename given to the AM486-DX4 development project. The project's name was Longhorn, and was targeted to directly compete with the Intel 486-DX2
Can somebody try LONGHORN/longhorn/Longhorn in the decrypt...

As far as I understand Longhorn has been renamed to VISTA so the next version of windows will be 'windows vista' don't know if that helps or complicates things..

[tsh]

Re: How hard would it be to rewrite RCC slightly????

[ramsfan]

Came across this website when looking for stuff about rc5.
http://dries.studentenweb.org/apt/packages/perl-Crypt-RC5/info.html
Upstream Kurt Kincaid
Static site hosted at Ulyssis. That's in Dutch, but there's a guide in english.
Sadly I think these are just coincidences, but thought I'd post in case they mean anything to anyone.

[/list]

[tsh]

OK, a reminder that I've forgotten how to code in C... Not sure this is much use to anyone, since it's not compiled for windows (well, there is a binary which I compiled under cygwin, but it doesn't seem to function. That could be my cygwin install though - it's new!)

I added a -v option, which lists each key, and it's output. This turned up that the masked sequence code didn't work - it was using DEADBEEF all the time. Tried to fix that, but failed to add a 'try all the permutations of upper and lower case'

A quick investigation shows that most of the time is taken with the decryption, not the key generation - so it matters little that it's not very efficient.

Sean

[Dickie911]

Is this less complicated than people think?

To qualify that I am very very new to the world of Perplexcity. I got some cards as a present from my wife and thought what's this cr*p. How wrong was I?!!!!!!

Perplex City has been ruling my life since Christmas day! I was lucky enough to get this card in one of the packets.

Could the 64/12/8 refer to a date such as 8th Dec 1964?

Teri Hatcher, the actress from Superman was born on 8th Dec 1964. (I tried Superman and it's not that! However, her dad was a nuclear physicist and her mum was a computer programmer!!! Could this be something?
http://www.moono.com/html/teri-hatcher/teri-hatcher-pictures.cfm

Is everyone getting unnecessarily diverted by all this coding??

Or am I just wishful thinking?!

[Dickie911]

OK, I have just gone back and read thru the earlier posts in more detail.

Ignore my earlier post.

My head hurts already.

But it feels great to be on the quest for an answer on this one! Just wish I was as brainy as some of you seem to be!

[Dickie911]

I have asked a friend who does Linux programming to have a look.

He is on the case.

He seems to think it will be easy, but to me it all seems like rocket science!!

LOL.

I'll post again if he comes up with anything.

[GasparLewis]

Glad to have you along Dickie, but be a doll and mind the Edit button to stop from multi-posting?

(Of course, I don't think that any variations of Superman were tried as the key [hey, it is eight letters...]. All about the back-from-holiday.)

[JTony]

[unfriction]

My first post to unfiction unforums, so Hi Folks!

In the story of Hercules, there were 12 labours...has anyone tried entering a solution reflecting this e.g. "none", "rest", "404" etc on the perplexcity.com site?

(As a sidebar, is there a resource anywhere where players can register their unsuccessful solutions, to help other players skip past em?

After some web-searching I found http://www.piney.com/CatullusMu.html it's interesting but I don't know who or what the source is.

Tried the following as decryption keys, but nothing interesting resulted:

"Hercules", "Herakles", "Dindymus", "Catullus", "Diagoras", "Virility", "Agdistis", "castrate", "cymbalum", "tympanum"

[unfriction]

For anyone who can install python and the pycrypto library, here's a short script (badly structured ) which you can experiment with.

Some assumptions (ASS out of U & ME) I made:

1) Encryption is ECB (Each 8 byte block of cryptotext is independent allowing us to shorten decryption time and only decode the first 8 bytes before checking for ascii chars instead of the whole cryptotext)

2) IV is empty

There may be other assumptions but none spring to mind right now.

I'll also post this as an attachment in case wrapping breaks it.

try:

data = "\x69\xA9\x3A\xFD\xC5\xAD\x43\x8F"

allowedKeyChars = """abcdefghijklmnoprstuvwy """
allowedKeyChars = allowedKeyChars[::-1]

allowedResultChars = """ ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789"""

import os
from Crypto.Cipher import RC5

for char7 in allowedKeyChars:
for char6 in allowedKeyChars:
for char5 in allowedKeyChars:
for char4 in allowedKeyChars:
for char3 in allowedKeyChars:
for char2 in allowedKeyChars:
for char1 in allowedKeyChars:
for char0 in allowedKeyChars:
key = char0 + char1 + char2 + char3 + char4 + char5 + char6 + char7
obj=RC5.new(key, RC5.MODE_ECB)
message = obj.decrypt(data)

if (message[0] in allowedResultChars) and \
(message[1] in allowedResultChars) and\
(message[2] in allowedResultChars) and\
(message[3] in allowedResultChars) and\
(message[4] in allowedResultChars) and\
(message[5] in allowedResultChars) and\
(message[6] in allowedResultChars) and\
(message[7] in allowedResultChars):
print "KEY:", key
print message

except Exception, msg:
print "Exception: %s" % msg
raise

[unfriction]

Leading spaces in the listing have indeed been suppressed so you'll need to use the attachment

[poozle]

Ahhhhh, I saw a small part of the hercules program on channel 4 earlier (in the UK) and thought, hmmm, that might be useful for "The Thirteenth Labour" and now I've forgotten it. NOOOOOOOOOO

Can't believe I forgot it, might have been really important.